(2x+5)(x^2-4x+3)=

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Solution for (2x+5)(x^2-4x+3)= equation: 


Simplifying
(2x + 5)(x2 + -4x + 3) = 0

Reorder the terms:
(5 + 2x)(x2 + -4x + 3) = 0

Reorder the terms:
(5 + 2x)(3 + -4x + x2) = 0

Multiply (5 + 2x) * (3 + -4x + x2)
(5(3 + -4x + x2) + 2x * (3 + -4x + x2)) = 0
((3 * 5 + -4x * 5 + x2 * 5) + 2x * (3 + -4x + x2)) = 0
((15 + -20x + 5x2) + 2x * (3 + -4x + x2)) = 0
(15 + -20x + 5x2 + (3 * 2x + -4x * 2x + x2 * 2x)) = 0
(15 + -20x + 5x2 + (6x + -8x2 + 2x3)) = 0

Reorder the terms:
(15 + -20x + 6x + 5x2 + -8x2 + 2x3) = 0

Combine like terms: -20x + 6x = -14x
(15 + -14x + 5x2 + -8x2 + 2x3) = 0

Combine like terms: 5x2 + -8x2 = -3x2
(15 + -14x + -3x2 + 2x3) = 0

Solving
15 + -14x + -3x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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